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Home/ Questions/Q 6841787
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:00:36+00:00 2026-05-27T00:00:36+00:00

lets say I have function trigger(){ $(‘a.pep’).each(function(){ $(‘a.pep’).click(function(){ console.log($(this).val()); }); }); } function push(){

  • 0

lets say I have

function trigger(){

    $('a.pep').each(function(){
            $('a.pep').click(function(){
            console.log($(this).val());
        });
    });
}
function push(){
    $('body').append('<a class="pep">hey mate i have no trigger yet</a>');
    trigger();  //now i do but the others have duplicated trigger
}
$(document).ready(function(){
     $('a.push').click(function(){
        push();
     });
});

So it seems that the click event is being applied twice/+ because the console.log is lauched more than once by click

How can i prevent this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:00:37+00:00Added an answer on May 27, 2026 at 12:00 am

    The problem is that you call $('a.pep').click() lots of times. (In fact, you bind as many click handlers as there are matching elements to each element. And then you do it again every time one of them is clicked.)

    You should lever the DOM event bubbling model to handle this. jQuery helps you with the on method:

    $(document.body).on('click', 'a.pep', function() {
        console.log('element clicked');
        $(document.body).append('<a class="pep">Click handlers handled automatically</a>');
    });
    

    See a working jsFiddle.

    Note that I have removed the val call, because a elements can’t have a value… Note also that the on method is introduced in jQuery 1.7; before that, use delegate:

    $(document.body).delegate('a.pep', 'click', function() {
    
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