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Home/ Questions/Q 8716409
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:04:14+00:00 2026-06-13T06:04:14+00:00

Let’s say I have my data in a 4 by 3 vector<vector<int> > as:

  • 0

Let’s say I have my data in a 4 by 3 vector<vector<int> > as:

1   2   3
4   5   6
7   8   9
10  11  12

and I want to delete every row containing the element 8 and end up like:

1   2   3
4   5   6
10  11  12

I have been trying to do:

for (vector<vector<int> >::iterator it = v.begin(); it != v.end(); it++) {
    if (find(it->begin(), it->end(), 8)) {
        // I will remove the row in here
    }
}

which gives me:

error: no matching function for call to 'find(std::vector<int>::iterator, std::vector<int>::iterator, int)'

I don’t have much experience with stl so I was wondering:

  • what’s wrong with my find call?
  • is it safe to remove an element from a vector while iterating over it?

Ofc any elegant solution to my problem is also welcomed..

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:04:15+00:00Added an answer on June 13, 2026 at 6:04 am

    what’s wrong with my find call?

    You probably forgot to #include <algorithm>

    is it safe to remove an element from a vector while iterating over it?

    Look into the erase-remove idiom – erasing vector elements can be tricky.

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