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Home/ Questions/Q 8220021
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T13:22:35+00:00 2026-06-07T13:22:35+00:00

Let’s say I have something like this: def find_the_best(array) temp = 15435435435 # sufficiently

  • 0

Let’s say I have something like this:

def find_the_best(array)
  temp = 15435435435 # sufficiently large number
  value = 0
  array.each do |element|
    some_var = function_does_something_complex_and_returns_value(element)
    some_var < temp ? value = element[0]
  end
end

This sufficiently large number solution works, but it seems kinda hacky. What’s the best way to handle this, particularly in ruby, but generally as well. The problem is that it really should be set to 0, then assigned the first value and then every value after that should be adopted only if it is smaller.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T13:22:38+00:00Added an answer on June 7, 2026 at 1:22 pm

    This doesn’t look like a sorting problem as much as best fit based on criteria.

    You’re looking for the smallest value, there is no need to have the temp value (unless there is something you aren’t telling us).

    Simply assume the first value will be the best and continue checking as you go.

    best_value = array[0];
    foreach( element in array )
    {
        if( best_value > element )
            best_value = element;
    }
    
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