Question

Lets say I have start=1, end=12 and the interval start:end.

I want to split it in bins of x=2 so that i will get a data frame of

 start.index end.index
1           1         2
2           3         4
3           5         6
4           7         8
5           9        10
6          11        12

In this case it results to 6 bins. start, end, and x are always integers

Is there any function to do this? Obvisouly when start%%x!=0 the one bin might be larger or smaller than the others but I dont mind.

Any help?

Answer 1

Here is a simple example of such a function:

foo <- function(start, end, x = 2) {
    SEQ <- seq(start, end, by = x)
    END <- SEQ + (x - 1)
    take <- END > end
    END[take] <- end
    data.frame(start.index = SEQ, end.index = END)
}

R> foo(1, 12, 2)
  start.index end.index
1           1         2
2           3         4
3           5         6
4           7         8
5           9        10
6          11        12
R> foo(1, 12, 3)
  start.index end.index
1           1         3
2           4         6
3           7         9
4          10        12
R> foo(1, 12, 4)
  start.index end.index
1           1         4
2           5         8
3           9        12

And with an odd number of observations so we get different bin widths for the last one:

R> foo(1, 11)
  start.index end.index
1           1         2
2           3         4
3           5         6
4           7         8
5           9        10
6          11        11