Question

Let’s say I have the 3 different forms defined in my view:

# views.py
form_one = FormOne()
form_two = FormTwo()
form_three = FormThree()

In my template:

<form action="" method="post" id="form-one">
  {{ form_one.as_table }}
  <input type="submit" value="Submit Form One" name="form-one" />
</form>

<form action="" method="post" id="form-two">
  {{ form_two.as_table }}
  <input type="submit" value="Submit Form Two" name="form-two" />
</form>

<form action="" method="post" id="form-three">
  {{ form_three.as_table }}
  <input type="submit" value="Submit Form Three" name="form-three" />
</form>

Assuming each form has their own unique field names, how do I handle all 3 forms from one view? I was thinking of the following method but I’m not sure if it’s the best way to tackle this issue:

# views.py

if request.method == 'POST':
    request_post = request.POST
    if 'form-one' in request_post:
        form_one = FormOne(request.POST)
    elif 'form-two' in request_post:
        form_two = FormTwo(request.POST)
    else:
        form_three = FormThree(request.POST)
else:
    form_one = FormOne()
    form_two = FormTwo()
    form_three = FormThree()

Any comments or suggestions?

Answer 1

I had a similar problem in a site I’m working on. I don’t have the code with me right now but I think I did something along these lines:

if request.method == 'POST': 
    valid = False
    form = FormOne(request.POST) 
    if form.is_valid():
        #handle case where use submitted FormOne
        valid = True

    form = FormTwo(request.POST) 
    if form.is_valid():
        #handle case where use submitted FormTwo
        valid = True

    form = FormThree(request.POST) 
    if form.is_valid():
        #handle case where use submitted FormThree
        valid = True

    if not valid:
        #handle case where none of the forms were valid