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Home/ Questions/Q 8895685
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T23:50:50+00:00 2026-06-14T23:50:50+00:00

Let’s say I have the following array of hashes: h = [{name => bob},

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Let’s say I have the following array of hashes:

h = [{"name" => "bob"}, {"car" => "toyota"}, {"age" => "25"}]

And I have the following key to match:

k = 'car'

How do I match the ‘k’ to ‘h’ and have delete every element after the match so that it returns:

h = [{"name" => "bob"}, {"car" => "toyota"}]
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  1. Editorial Team
    Editorial Team
    2026-06-14T23:50:51+00:00Added an answer on June 14, 2026 at 11:50 pm

    I like megas’ version, as its short and to the point. Another approach, which would be more explicit, would be iterating over the keys array of each hash. The keys of a hash are maintained in an ordered array (http://ruby-doc.org/core-1.9.3/Hash.html). They are ordered by when they were first entered. As a result, you can try the following:

    newArray = Array.new
    h.each do |hash| # Iterate through your array of hashes
        newArray << hash
        if hash.has_key?("car") # check if this hash is the "car" hash.
          break # exits the block
        end
    end
    

    This all depends, of course, on whether the array was created in the proper order. If it was, then you’re golden.

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