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Home/ Questions/Q 6160951
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:24:20+00:00 2026-05-23T21:24:20+00:00

Let’s say I have the following in C or C++: #include <math.h> #define ROWS

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Let’s say I have the following in C or C++:

#include <math.h>
#define ROWS 15
#define COLS 16
#define COEFF 0.15
#define NODES (ROWS*COLS)
#define A_CONSTANT (COEFF*(sqrt(NODES)))

Then, I go and use NODES and A_CONSTANT somewhere deep within many nested loops (i.e. used many times). Clearly, both have numeric values that can be ascertained at compile-time, but do compilers actually do it? At run-time, will the CPU have to evaluate 15*16 every time it sees NODES, or will the compiler statically put 240 there? Similarly, will the CPU have to evaluate a square root every time it sees A_CONSTANT?

My guess is that the ROWS*COLS multiplication is optimized out but nothing else is. Integer multiplication is built into the language but sqrt is a library function. If this is indeed the case, is there any way to get a magic number equivalent to A_CONSTANT such that the square root is evaluated only once at run-time?

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:24:21+00:00Added an answer on May 23, 2026 at 9:24 pm

    It depends on your compiler.

    #include <math.h>
    
    #define FOO sqrt(5);
    
    double
    foo()
    {
      return FOO;
    }
    

    My compiler (gcc 4.1.2) generates the following assembly for this code:

    .LC0:
        .long   2610427048
        .long   1073865591
        .text
        .p2align 4,,15
    .globl foo
        .type   foo, @function
    foo:
    .LFB2:
        movsd   .LC0(%rip), %xmm0
        ret
    .LFE2:
    

    So it does know that sqrt(5) is a compile-time constant.

    If your compiler is not so smart, I do not know of any portable way to compute a square root at compile time. (Of course, you can compute the result once and store it in a global or whatever, but that is not the same thing as a compile-time constant.)

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