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Lets say I have the following:
int i = 1;
String str("abc");
Would str be consider a constant expression?
From lots of C++ books, it seems a constant expression must be evaluated to an integral type.
No, it won’t. In C++11 there is a new keyword
constexprintroduced that helps generalize the notion of constant expressions. IfStringconstructor from"abc"is trivial enough then it could be declaredconstexpr; however such constructor probably has to allocate memory so it wouldn’t qualify.