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Home/ Questions/Q 4103868
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T21:00:54+00:00 2026-05-20T21:00:54+00:00

Let’s say I have these arrays my @new = qw/a b c d e/;

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Let’s say I have these arrays

my @new = qw/a b c d e/;
my @old = qw/a b   d e f/;

and I would like to them compared, so I get 3 new arrays containing the differences

  • an array with the elements that are in @new and not in @old : c
  • an array with the elements that are not in @new and in @old : f
  • an array with the elements that are in both @new and @old : a b d e

I am thinking about the exists function, but that only works for hashes I suppose.

Update: I messed up the letter examples.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T21:00:54+00:00Added an answer on May 20, 2026 at 9:00 pm

    Here’s a function that I’ve used many, many times.

    sub compute_sets {
        my ($ra, $rb) = @_;
        my (@a, @b, @ab, %a, %b, %seen);
    
        @a{@$ra} = ();
        @b{@$rb} = ();
    
        foreach (keys %a, keys %b) {
            next if $seen{$_}++;
    
            if (exists $a{$_} && exists $b{$_}) {
                push(@ab, $_);
            }
            elsif (exists $a{$_}) {
                push(@a, $_);
            }
            else {
                push(@b, $_);
            }
        }
    
        return(\@a, \@b, \@ab);
    }
    

    It returns references to arrays containing the elements in the first/second/both lists:

    my @new = qw/a b c d e/;
    my @old = qw/a b   d e f/;
    
    my ($new_only, $old_only, $both) = compute_sets(\@new, \@old);
    
    say 'new only: ', join ' ', @$new_only; # c
    say 'old only: ', join ' ', @$old_only; # f
    say 'both: ', join ' ', @$both;         # e a b d
    
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