Question

Let’s say I have these two functions:

$(".a").animate(
        {"left":"100%"},
        {duration:10000, complete:function(){
             //Something is triggered!! e.g 
             alert("a");
            //Please note: In actual case it is never as simple as alert("a").
        }}
);

$(".b").mouseover(function(){
    $(".a").stop().animate({"top":"100px"},{duration:5000});
});

• According to these, .a would stop as long as .b is
  mouseover-ed and animate({"top":"100px"},{duration:5000}) would
  be triggered.

• But I want it to alert("a") once when .b is mouseover-ed
  and then trigger animate({"top":"100px"},{duration:5000}).

However, I can’t set the second function this way:

$(".b").mouseover(function(){
        //something happens! e.g
        alert("a");
        $(".a").stop().animate({"top":"100px"},{duration:5000});
    });

• It would alert("a") twice if .b is mouseover-ed after .a done
  animate.

I’ve tried stop()‘s jumpToEnd parameter and it is not ideal

Whenever .b is mouseover-ed , .a‘s animte would complete instantly and .a would be shifted to left:100%. I want it to stop at where it is and yet alert("a") before second animate being triggered

---

I would be extremely grateful if someone can provide a fast and easy solution for this!

Answer 1

$(".a").animate(
        {"left":"100%"},
        {duration:10000, complete:myAfterWork} // Use the function name only
);

$(".b").mouseover(function(){
    myAfterWork();
    $(".a").stop().animate({"top":"100px"},{duration:5000});
});

function myAfterWork()
{
  if($(".a").is(":animated"))
  {
    //Access $(".a") here and do your job

    //Note if you use $(this) in place of $(".a") it will be different 
    //when called from .a's animation than from .b's animation
  }

}