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Home/ Questions/Q 6732481
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:39:23+00:00 2026-05-26T10:39:23+00:00

Let’s say I have this directory structure. <Directory Id=TARGETDIR Name=SourceDir> <Directory Id=test Name=test> <Component

  • 0

Let’s say I have this directory structure.

<Directory Id="TARGETDIR" Name="SourceDir">
  <Directory Id="test" Name="test">
    <Component Id="file" Guid="*">
      <File Id="file" Source="file.dll"></File>
    </Component>
  </Directory>
</Directory>

This will install file.dll into C:\test. What I want to do is during the install overwrite where that file directory with C:\newpath\ and install the file there instead. I have tried this with a Custom Action with no luck. I do see the debug line written so I know it’s being called, it’s just the file is still installed in C:\test

<InstallExecuteSequence>
  <Custom Action="OverwriteDir" After="CostFinalize" />  
</InstallExecuteSequence>

[CustomAction]
public static ActionResult OverwriteDir(Session session)
{
     System.Diagnostics.Debug.WriteLine(session["tester"]);
     session["tester"] = "C:\\newpath";
     return ActionResult.Success;
}

What can I do differently?

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:39:23+00:00Added an answer on May 26, 2026 at 10:39 am

    First you need to make sure that the folder which contains your file inside the MSI uses a public installer property (no lowercase letters in its name) as its ID. The best solution is TARGETDIR because its already configured.

    After that, you can use one of these custom action to change the property value during install:

    • a custom action which changes the directory property value scheduled before CostFinalize
    • a type 35 custom action which changes the directory path (should be scheduled after CostFinalize)
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