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Home/ Questions/Q 8987769
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T21:52:15+00:00 2026-06-15T21:52:15+00:00

Let’s say I have this following code: <?php $i = 1; $user_login = some_name;

  • 0

Let’s say I have this following code:

<?php           
    $i = 1;
    $user_login = "some_name";

    do {
        $user_login_tmp = $user_login . "_" . ($i++);
        echo $user_login_tmp . "\n";
    } while ($i<10);
?>

As seen in this demo(clickable!), the first echo echoes some_name_1.
This seems kinda weird to me since there is $i++ there.
How come that the first output isn’t ..._2? Am I missing something?

I tried looking for an answer in the PHP manual page of the do-while loop but I couldn’t find my answer there…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T21:52:17+00:00Added an answer on June 15, 2026 at 9:52 pm

    $i++ Post-increments, it means: return $i and then increments $i by one.

    The demo’s output will start with ..._2 if you change the code to (++$i) (new demo)

    Check out the PHP.net’s page about the incrementing operator:

    http://php.net/manual/en/language.operators.increment.php

    ++$a    Pre-increment   Increments $a by one, then returns $a.
    
    $a++    Post-increment  Returns $a, then increments $a by one.
    
    --$a    Pre-decrement   Decrements $a by one, then returns $a.
    
    $a--    Post-decrement  Returns $a, then decrements $a by one.
    
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