Question

Let’s say I have this form:

class SimpleUploadForm(forms.Form):
   file = forms.FileField()

I have this model:

class MyModel(models.Model):
   first_file = models.FileField(upload_to="uploads/%Y/%m/%d",storage=MyCustomStorage())
   second_file = models.FileField(upload_to="uploads/%Y/%m/%d",storage=MyCustomStorage())

for which I also provide a ModelForm. The view part for the SimpleUploadForm is like this:

def simple_upload(request):
   ...
   if request.method == "POST":
      form = SimpleUploadForm(request.POST,request.FILES)
      if form.is_valid():
         # what do I need to do here to save the file in the same place where the `MyModel` ModelForm is saving them?
      else:
        ...

I don’t know how to use the storage and upload_to fields without a ModelForm.

Answer 1

You can use your storage like any other class. Its API is well-documented.

Or you can set DEFAULT_FILE_STORAGE in settings.py, and it will be used automatically for all your file operations.