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Home/ Questions/Q 7932551
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:03:19+00:00 2026-06-03T21:03:19+00:00

Let’s say I have this XML file: <Names> <Name> <FirstName>John</FirstName> <LastName>Smith</LastName> </Name> <Name> <FirstName>James</FirstName>

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Let’s say I have this XML file:

<Names>
    <Name>
        <FirstName>John</FirstName>
        <LastName>Smith</LastName>
    </Name>
    <Name>
        <FirstName>James</FirstName>
        <LastName>White</LastName>
    </Name>
</Names>

And now I want to print all the names of the node:

Names
Name
FirstName
LastName

I managed to get the all in a XmlNodeList, but I dont know how SelectNodes works.

XmlNodeList xnList = xml.SelectNodes(/*What goes here*/);

I want to select all nodes, and then do a foreach of xnList (Using the .Value property I assume).

Is this the correct approach? How can I use the selectNodes to select all the nodes?

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  1. Editorial Team
    Editorial Team
    2026-06-03T21:03:20+00:00Added an answer on June 3, 2026 at 9:03 pm

    Ensuring you have LINQ and LINQ to XML in scope:

    using System.Linq;
    using System.Xml.Linq;
    

    If you load them into an XDocument:

    var doc = XDocument.Parse(xml);    // if from string
    var doc = XDocument.Load(xmlFile); // if from file
    

    You can do something like:

    doc.Descendants().Select(n => n.Name).Distinct()
    

    This will give you a collection of all distinct XNames of elements in the document. If you don’t care about XML namespaces, you can change that to:

    doc.Descendants().Select(n => n.Name.LocalName).Distinct()
    

    which will give you a collection of all distinct element names as strings.

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