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Home/ Questions/Q 726693
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:28:52+00:00 2026-05-14T06:28:52+00:00

Let’s say I have two classes, A and B, where B is a child

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Let’s say I have two classes, A and B, where B is a child class of A.

I also have the following function:

void foo(boost::shared_ptr<const A> a)
{
    boost::shared_ptr<const B> b = boost::dynamic_pointer_cast<const B>(a); // Error !
}

Compilation with gcc gives me the following errors:

C:\Boost\include/boost/smart_ptr/shared_ptr.hpp: In constructor 'boost::shared_ptr< <template-parameter-1-1> >::shared_ptr(const boost::shared_ptr<Y>&, boost::detail::dynamic_cast_tag) [with Y = const A, T = const B]':
C:\Boost\include/boost/smart_ptr/shared_ptr.hpp:522:   instantiated from 'boost::shared_ptr<X> boost::dynamic_pointer_cast(const boost::shared_ptr<U>&) [with T = const B, U = const A]'
src\a.cpp:10:   instantiated from here
C:\Boost\include/boost/smart_ptr/shared_ptr.hpp:259: error: cannot dynamic_cast 'r->boost::shared_ptr<const A>::px' (of type 'const class A* const') to type 'const class B*' (source type is not polymorphic)

What could possibly be wrong ?

Thank you.

EDIT

Actually, I found out how to avoid this, but I’m not sure to understand.

My A class was empty (and thus had no virtual destructor). If I add a virtual destructor, the error goes out. But I don’t get it, why is this required ?

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:28:52+00:00Added an answer on May 14, 2026 at 6:28 am

    dynamic_pointer_cast uses the C++ dynamic_cast internally and dynamic_cast requires your classes to have at least one virtual method. No virtual methods means no vtable and without vtable dynamic_cast would not be able to figure which casts are doable at run-time.

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