Question

Let’s say I have two models looking like this:

class ProductType(models.Model):
    product_type = models.CharField(max_length=100)

class Product(models.Model):
    name = models.CharField(max_length=200)
    slug = models.SlugField()

    product_type = models.ForeignKey(ProductType)

    score = models.PositiveIntegerField(default=0)

Now I want to fetch the top two products (the two with highest score) from each ProductType.
So if I have Phones, Computers, TVs as ProductTypes I want the two best Phones, Computers, TVs.

As I don’t even know how to do this in MySQL I’ve tried searching for the MySQL-solution but the ones I find is extremely complex and this doesn’t feel like an extremely complex thing to do.

I am leaning towards making an own model for the top products and have a cronjob to fix this, but I’d like to see if there’s an easier solution to this.

Answer 1

Well, you could make a method inside of the ProductType class that returns the top two results for its products:

class ProductType(models.Model):
    product_type = models.CharField(max_length=100)

    def TopTwoProducts(self):
        return self.product_set.order_by('-score')[0:2]

Then you would just do something like:

for type in ProductType.objects.all():
    type.TopTwoProducts()