Question

Let’s say I list a list of rows with a link like this:

content.php

/*DATABASE CONNECTION AND SQL STUFF*/

<div id='content'>

  <?php 

    $sql = mysql_query ("SELECT id, somedata FROM myTable");

    while ($row = mysql_fetch_assoc($sql)) {

    echo "<a href='?p=moreData&id=" . $row['id'] . "'>" . $somedata . "</a><br />\n";

    }

  ?>

</div>

moreData.php

<?php

  $id = $_GET['id'];

  /* SQL STUFF */

  echo "More information about" . " ". $somedata. " " . "wich has an id of" . " " . $id;

How can I use the moreData.php to be loaded with $_GET information inside a new div called <div id='ajaxContent'> in the file content.php instead of loading a new page?

I’ve read some about jQuery load but i’m very new to jQuery coding and I cannot figure it out by myself…

Answer 1

You need to preset an javascript var rowId with the id you want to sent via GET to moreData.php. I would set it as rel attribute to the tag and fetch it when I handle the click event.

echo "<a class='ajaxCall' rel='" . $row['id'] . "' href='?p=moreData&id=" . $row['id'] . "'>" . $somedata . "</a><br />\n";

and then the click event

$('a.ajaxCall').click(function() {
  var rowId = $(this).attr('rel');
}); 

and in the same event the ajax call

$.ajax({
  type: "get",
  url: '/moreData.php', // your uri to the moredata
  data: { id: rowId },
  success: function(data) { // data is the response of the ajax call
    $('#ajaxContent').html(data);
  }
}); 

You need jQuery library.