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Home/ Questions/Q 3975020
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T04:38:09+00:00 2026-05-20T04:38:09+00:00

Lets say I want to set up a basic text encoding using a dictionary

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Lets say I want to set up a basic text encoding using a dictionary in python.

Two ways of doing this come to mind immediately – using zip, and using list comprehension.

characters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ .,!;"
dict_a = dict((x, characters[x]) for x in xrange(0, 31))
dict_b = dict(zip(xrange(0, 31), characters))

Which of these is more efficient? (The real encoding is longer than 31, this is a toy example). Is the difference significant?

Alternatively, am I approaching this wrong and should be using something other than a dictionary? (I need to be able to go in both directions of encoding).

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  1. Editorial Team
    Editorial Team
    2026-05-20T04:38:09+00:00Added an answer on May 20, 2026 at 4:38 am

    The enumerate function is probably the easiest way to create your dict:

    dict_c = dict(enumerate(characters))
    

    However, I’m not sure what that gives you that you can’t do with the string. The following seem equivalent to me:

    >>> dict_c[3]
    'D'
    >>> characters[3]
    'D'
    
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