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Home/ Questions/Q 665181
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:40:53+00:00 2026-05-13T23:40:53+00:00

Lets say I’ve got a table listing car brands or models: Cars : Id

  • 0

Lets say I’ve got a table listing car brands or models:

Cars:

Id | Brand
-----------
1  | BMW
2  | Audi
3  | Volvo

And I’ve also got another table which links features.
Link:

Id | carid | featureid
-----------------------
1  | 1     | 1
2  | 1     | 2
3  | 2     | 2
4  | 3     | 1
5  | 3     | 2
6  | 3     | 3

And I’ve got the table listing the features.
Features:

Id | Feature
-----------
1  | A/C
2  | 4WD
3  | Heated seats

I want to list these results on my front page like this:

BMW

  • A/C
  • 4WD

Audi

  • 4WD

Volvo

  • A/C
  • 4WD
  • Heated seats

What’s the best/most efficient way of doing this (using PHP and MySQL)?


Edit:
I think I’m going to redesign my Cars database to look like this instead:

Id | Brand   | Feature
----------------------
1  | BMW     | 1,2
2  | Audi    | 1
3  | Volvo   | 1,2,3
4  | Citröen | 

And then fetch Features beforehand and combine in PHP. I guess it’s much easier, and I don’t get a problem if I have a brand without a feature.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:40:53+00:00Added an answer on May 13, 2026 at 11:40 pm
    SELECT Cars.Brand As Brand, Features.Feature as Feature FROM Cars, Link, Features WHERE Cars.id = Link.carid AND Features.id = Link.featureid Order By Brand
    

    This should be the query, then use mysql_fetch_array and print the results

    <?php
      $result=mysql_query($query);
      $last='';
      while($row = mysql_fetch_array($result)){
         if($row['brand']!=$last) {
                 //if the previous brand is the same don't print it out
                 //otherwise save the new brand and print it out
                 $last=$row['brand'];
                 echo "<b>".$row['brand']."</b><br>";
                 }
         echo $row['Feature'] . "<br>";    
      }
    ?>
    
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