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Home/ Questions/Q 9252487
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T10:57:25+00:00 2026-06-18T10:57:25+00:00

Let’s say I’ve pulled down the Twitter graph local to myself into Neo4J. I

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Let’s say I’ve pulled down the Twitter graph local to myself into Neo4J. I want to find people who follow my friends in number larger that should be expected. More specifically, I want to find people who follow the people I follow, but I want the results to be sorted so that the person following the highest number of my friends is sorted first. Possible in Cypher?

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  1. Editorial Team
    Editorial Team
    2026-06-18T10:57:26+00:00Added an answer on June 18, 2026 at 10:57 am

    Here’s a console example:

    http://console.neo4j.org/r/p36cgj

    create (me {n:"a"}), (fo1 {n:"fo1"}), (fo2 {n:"fo2"}), (fo3 {n:"fo3"}), (fr1 {n:"fr1"}),
    (fr2 {n:"fr2"}), (fr3 {n:"fr3"}),
    fo1-[:follows]->me, fo2-[:follows]->me, fo3-[:follows]->me, me-[:follows]->fr1, 
    me-[:follows]->fr2, me-[:follows]->fr3, fo1-[:follows]->fr1, fo2-[:follows]->fr2, 
    fo1-[:follows]->fr2, fo1-[:follows]->fr3;
    
    
    start me=node:node_auto_index(n="me") 
    match me-[:follows]->friends<-[:follows]-follower-[:follows]->me 
    return follower, count(friends) as creepinessFactor, length(me-[:follows]->()) as countIFollow 
    order by creepinessFactor desc;
    

    I’m curious to hear the results, btw. 😛

    You could also throw in a where like:

    where not(me-[:follows]->follower)
    

    To avoid getting friends within your circle.

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