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Home/ Questions/Q 982973
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T04:46:56+00:00 2026-05-16T04:46:56+00:00

Let’s say I’ve this a checkbox and a div that contains elements that I

  • 0

Let’s say I’ve this a checkbox and a div that contains elements that I want to hide/display depending on the checkbox being checked or not.

<input type = "checkbox" id = "myCheckbox"/>
<div id = "display-hide">
  //Contains more elements
</div>

Now, here is the JQuery script that does the trick.

<script type = "text/javascript">
  $(function () {
    $("#myCheckbox").click(function(){
        $("#display-hide").toggle(this.checked);
     });
      $("#display-hide").hide();
  });    
</script>

The first time I access the page, everything works fine (i.e. div is hidden – when I check the checkbox, the div is displayed).

BUT, when I come back to the page (to edit, for instance), no-matter the value of the checkbox (checked or not), the div is hidden first. The div becomes only visible after I uncheck then check again.

I guess that because of this statement:

$("#display-hide").hide();

Is there anyway to verify the value of the checkbox and hide/show the div accordingly?

Thanks for helping

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  1. Editorial Team
    Editorial Team
    2026-05-16T04:46:57+00:00Added an answer on May 16, 2026 at 4:46 am

    Instead of this:

    $("#display-hide").hide();
    

    You can use .triggerHandler(), like this:

    $("#myCheckbox").triggerHandler('click');
    

    This executes the click handler your just bound without actually executing a click on the box, so it makes the initial state match, without interfering. Overall it looks like this:

    $("#myCheckbox").click(function(){
      $("#display-hide").toggle(this.checked);
    }).triggerHandler('click');
    

    You can give it a try here

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