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Home/ Questions/Q 6719485
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:05:55+00:00 2026-05-26T09:05:55+00:00

Let’s say that I have a type like this (that works): data WAE =

  • 0

Let’s say that I have a type like this (that works):

data WAE = Num Float
         | Id String
         | With [(String, WAE)] WAE -- This works, but I want to define it as below
         deriving(Eq, Read, Show)

I want a type like this (doesn’t work):

data WAE = Num Float
         | Id String
         | With [(Id, WAE)] WAE -- This doesn't work ("Id not in scope")
         deriving(Eq, Read, Show)

Why can’t I do that in Haskell? Any ideas in achieveing a similar effect?

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:05:55+00:00Added an answer on May 26, 2026 at 9:05 am

    Based on your question, I’m not entirely sure what you are trying to accomplish. Here are two possibilities that are possible with Haskell’s type-system.

    data WAE = Num Float
             | Id String
             | With [(WAE, WAE)] WAE
             deriving (Eq, Read, Show)
    

    I’m not sure this is what you want, however, because it allows for more than just an id in the first portion of the pair.

    Another possibility is to create a new type (or alias) for the id, like so:

    data MyId = MyId String deriving (Eq, Read, Show)
    data WAE = Num MyId Float
             | Id MyId
             | With [(MyId, WAE)] WAE 
             deriving (Eq, Read, Show)
    

    Note that MyId could also be created with either newtype or type, each giving a slightly different meaning.

    You cannot, however use Id as it is a data-constructor, where a type is expected.

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