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Home/ Questions/Q 4029886
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:24:06+00:00 2026-05-20T11:24:06+00:00

Let’s say that I have declared an NSString like this NSString *myString = [[NSString

  • 0

Let’s say that I have declared an NSString like this

NSString *myString = [[NSString alloc] initWithString:@"Never Heard"];
NSString *tempString;

tempString = myString;

[myString release];

My question is why does it work? As you can see, I didn’t alloc for the tempString.
Therefore I don’t think there is a need to release it. But if I try to alloc and init
the tempString, it will bring an error.

NSString *myString = [[NSString alloc] initWithString:@"Never Heard"];
NSString *tempString = [[NSString alloc] init];

tempString = myString;

[myString release];

I use NSString as example, but instead I have different classes implemented. I’m
trying to emphasize how memory allocation works here. Care to clarify and explain?

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:24:07+00:00Added an answer on May 20, 2026 at 11:24 am

    A pointer is simply a memory address. You only create one object, and then you point tempString to that object. And tempString == myString.

    [myString release] deallocates the string, leaving both pointers pointing at deallocated memory.

    Do no confuse variables with objects. Variables are simply are handles that you use to access objects. Creating a new variable does not mean you are creating a new object.

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