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Home/ Questions/Q 3460040
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T10:10:53+00:00 2026-05-18T10:10:53+00:00

Let’s say that we have an array with n elements (n > 0). We

  • 0

Let’s say that we have an array with n elements (n > 0).

We would like to output a list of those elements, with a separator between them.

A common approach to this problem is:

foreach item
  (
    output item
    output separator
  )
trim last separator

But it seems a bit messy to have to do that.

Another approach would be:

check that there is at least one element
loop
  (
     output element
     next element, or break if no more elements
     output separator
  )

But I am not sure that it will always work.

Do you see other clever ways to do that, for example in C, C++?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T10:10:54+00:00Added an answer on May 18, 2026 at 10:10 am
    char *sep = "";
    for (i = 0; i < size; ++i) {
        printf("%s%s", sep, item[i]);
        sep = ", ";
    }
    
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