Question

Let’s say the first N integers divisible by 3 starting with 9.

I’m sure there is some one line solution using lambdas, I just don’t know it that area of the language well enough yet.

Answer 1

Just to be different (and to avoid using a where statement) you could also do:

var numbers = Enumerable.Range(0, n).Select(i => i * 3 + 9); 

Update This also has the benefit of not running out of numbers.