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Home/ Questions/Q 7410727
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T06:16:40+00:00 2026-05-29T06:16:40+00:00

Let’s say there is a graph and some set of functions like: create-node ::

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Let’s say there is a graph and some set of functions like:

create-node :: Graph -> (Graph, Node)
split-node :: Graph -> Node -> (Graph, Node, Node)

I would like to create versions of those functions that don’t expect Graph as an argument, mainly for convenience (preferably without monads so I wouldn’t need to wrap every graph manipulating piece of code in a monad block). So what about this:

create-node :: (Graph -> (Graph, Node))
split-node :: (Graph -> Node) -> ((Graph -> Node), (Graph -> Node))

Or more generally:

fun :: (Graph -> Argument) -> ... -> (Graph -> Result)

I would then be able to use the (Graph -> ...) values as if they were normal nodes. In the end, to get a real graph out of a (Graph -> ...) value, just apply it to an empty graph. Is this a reasonable approach?

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  1. Editorial Team
    Editorial Team
    2026-05-29T06:16:41+00:00Added an answer on May 29, 2026 at 6:16 am

    Ok, so

    create-node :: (Graph -> (Graph, Node))
    

    is the state monad, just without the fancy newtype (and a flipped return value). So I don’t see the advantage of not using State here. After all that lets me write fairly clean code using the state Monad:

     reverseEdgesM :: State Graph ()
     reverseEdgesM = do --...
    

    Then pop out of it whenever I’ve got some pure code to run using runState and friends:

     reverseEdges :: Graph -> Graph
     reverseEdges = execState reverseEdgesM
    

    If you do want to push forward with your functions idea, you may want to look into difference lists to see how its done with simple lists.

    Also, if you’ve just got some algorithms to implement, you may want to look into existing functional graph data structure libraries (like fgl), rather than rolling your own. If you want to understand the theory, check out Erwig’s paper on inductive graphs.

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