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Home/ Questions/Q 4014686
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T09:31:37+00:00 2026-05-20T09:31:37+00:00

let’s say we have the following text: 1 a,2 b,3 c,4 d and the

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let’s say we have the following text: “1 a,2 b,3 c,4 d” and the following expression: /\d (\w)/g

what we want to do is to extract a, b, c, d as denoted by the regular expression.

unfortunately “1 a,2 b,3 c,4 d”.match(/\d (\w)/g) will produce an array: 1 a,2 b,3 c,4 d and RegExp.$1 will contain only the groups from the last match, i.e. RegExp.$1 == ‘d’.

how can I iterate over this regex so that I can extract the groups as well… I am looking for a solution that is also memory efficient, i.e. some sort of iterator object

EDIT:
It needs to be generic. I am only providing a simple example here. One solution is to loop over the array and reapply the regex for each item without the global flag but I find this solution a bit stupid although it seems to be like the only way to do it.

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  1. Editorial Team
    Editorial Team
    2026-05-20T09:31:37+00:00Added an answer on May 20, 2026 at 9:31 am
    var myregexp = /\d (\w)/g;
    var match = myregexp.exec(subject);
    while (match != null) {
        // matched text: match[0]
        // match start: match.index
        // capturing group n: match[n]
        match = myregexp.exec(subject);
    }
    

    (shamelessly taken from RegexBuddy)

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