Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 547931
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T11:01:34+00:00 2026-05-13T11:01:34+00:00

Let’s say we have the following XML: <root> <row> <column>row 1 col 1</column> <column>row

  • 0

Let’s say we have the following XML:

<root>
  <row>
    <column>row 1 col 1</column>
    <column>row 1 col 2</column>
    <column>row 1 col 3</column>
  </row>
  <row>
    <column>row 2 col 1</column>
    <column>row 2 col 2</column>
    <column>row 2 col 3</column>
  </row>
  <row>
    <column>row 3 col 1</column>
    <column>row 3 col 2</column>
    <column>row 3 col 3</column>
  </row>
</root>

How do I transpose this, using T-SQL XQuery to:

<root>
    <column>
        <row>row 1 col 1</row>
        <row>row 2 col 1</row>
        <row>row 3 col 1</row>
    </column>
    <column>
        <row>row 1 col 2</row>
        <row>row 2 col 2</row>
        <row>row 3 col 2</row>
    </column>
    <column>
        <row>row 1 col 3</row>
        <row>row 2 col 3</row>
        <row>row 3 col 3</row>
    </column>
</root>
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T11:01:34+00:00Added an answer on May 13, 2026 at 11:01 am

    I suspect there might be a really nice approach using PIVOT, but I don’t know it well enough to be able to say for sure. What I offer here works. I have split it up into chunks for better formatting and to provide commentary:

    To start with let’s capture the example data

    -- Sample data
    DECLARE @x3 xml
    
    SET @x3 = '
    <root>
      <row>
        <column>row 1 col 1</column>
        <column>row 1 col 2</column>
        <column>row 1 col 3</column>
      </row>
      <row>
        <column>row 2 col 1</column>
        <column>row 2 col 2</column>
        <column>row 2 col 3</column>
      </row>
      <row>
        <column>row 3 col 1</column>
        <column>row 3 col 2</column>
        <column>row 3 col 3</column>
      </row>
    </root>
    '
    
    DECLARE @x xml
    SET @x = @x3
    
    -- @x is now our input
    

    Now the actual transposing code:

    Establish the size of the matrix:

    WITH Size(Size) AS
    (
        SELECT CAST(SQRT(COUNT(*)) AS int) 
        FROM @x.nodes('/root/row/column') T(C)
    )
    

    Shred the data, use ROW_NUMBER to capture the index (the -1 is to make it zero based), and use modulo and integer divide on the index to work out the new row and column numbers:

    ,Flattened(NewRow, NewCol, Value) AS
    (
        SELECT
            -- i/@size as old_r, i % @size as old_c, 
            i % (SELECT TOP 1 Size FROM Size) AS NewRow, 
            i / (SELECT TOP 1 Size FROM Size) AS NewCol, 
            Value
        FROM (
            SELECT
                (ROW_NUMBER() OVER (ORDER BY C)) - 1 AS i, 
                C.value('.', 'nvarchar(100)') AS Value
            FROM @x.nodes('/root/row/column') T(C)
            ) ShreddedInput
    )
    

    With this CTE FlattenedInput available, all we now need to do is get the FOR XML options and query structure right and we’re done:

    SELECT
        (
            SELECT Value 'column'
            FROM
                Flattened t_inner
            WHERE
                t_inner.NewRow = t_outer.NewRow
            FOR XML PATH(''), TYPE
        ) row
    FROM
        Flattened t_outer
    GROUP BY NewRow
    FOR XML PATH(''), ROOT('root')
    

    Sample output:

    <root>
      <row>
        <column>row 1 col 1</column>
        <column>row 2 col 1</column>
        <column>row 3 col 1</column>
      </row>
      <row>
        <column>row 1 col 2</column>
        <column>row 2 col 2</column>
        <column>row 3 col 2</column>
      </row>
      <row>
        <column>row 1 col 3</column>
        <column>row 2 col 3</column>
        <column>row 3 col 3</column>
      </row>
    </root>
    

    Works on any size ‘square’ data. Note the lack of sanity checking / error handling.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 262k
  • Answers 262k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer Easy; just project onto a POCO (or anonymous) type: var… May 13, 2026 at 11:50 am
  • Editorial Team
    Editorial Team added an answer Since the expression passed into your Zap method is a… May 13, 2026 at 11:50 am
  • Editorial Team
    Editorial Team added an answer Generally, most people will tell you to avoid global variables… May 13, 2026 at 11:50 am

Related Questions

I have a French site that I want to parse, but am running into
Let's say you create a wizard in an HTML form. One button goes back,
Let's say I'm building a data access layer for an application. Typically I have
Let's say you have a class called Customer, which contains the following fields: UserName
Let me try to explain what I need. I have a server that is

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.