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Home/ Questions/Q 8840735
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T10:31:59+00:00 2026-06-14T10:31:59+00:00

Let’s say you get a string of array-Dimensions from the Database. It would look

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Let’s say you get a string of array-Dimensions from the Database. It would look something like this: "[1][2][1]" now you have a corresponding value, we shall call it B

I have to create an array of this format: (x,(B))

if another Value, we call it A had this Dimension-String: [1][1], the array shall be filled like this: (A,(B))

and if by chance there is another Value named C with the String[1][2][2] the array is supposed to look like this: (A,(B,C))

i thought of something like :

Redim Array1(1)
Redim Array2(1)
Array1(0) = A
Array2(0) = B
Array2(1) = C
Array1(1) = Array2()

But that in a dynamic way. It seems to me, that vba does not support nested arrays.
Unfortunately a Multi-dimensional array will not work, as the “dimensions” are not consistent. any help appreciated

Edit:
tried:

c = 0
dim array1() as Variant
redim preserve array1(c)
array1(c) = split(mid("[1][4]",2,len("[1][4]")-2),"][")

and it gave me a type mismatch error

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T10:32:01+00:00Added an answer on June 14, 2026 at 10:32 am

    This works:

    Private Sub testArray()
      Dim DynamicArray1() As Variant
      Dim DynamicArray2() As Variant
    
      ReDim DynamicArray1(1)
      ReDim DynamicArray2(1)
      DynamicArray1(0) = "A"
    
      DynamicArray2(0) = "B"
      DynamicArray2(1) = "C"
    
      DynamicArray1(1) = DynamicArray2
    End Sub
    
    Sub test2()
      Dim c As Integer: c = 0
      Dim array1() As Variant
      ReDim Preserve array1(c)
      array1(c) = Split(Mid("[1][4]", 2, Len("[1][4]") - 2), "][")
    End Sub
    
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