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Home/ Questions/Q 6477351
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:56:16+00:00 2026-05-25T06:56:16+00:00

Let’s say you have a type T and subtypes TSub1 , TSub2 etc. Several

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Let’s say you have a type T and subtypes TSub1, TSub2 etc.

Several of these subtypes are initialised with new TSub(...). The resulting pointers are then stored as elements in:

list<T*> tsList;

The same pointers are also used as keys in:

map<T*,V> tsMap;

Now consider an iteration over tsList, with iterator variable tIter.

Here are my questions:

  1. Will tsMap[*tIter] and tsMap.find(*tIter) both successfully
    find the correct associated value?

  2. Will delete *tIter successfully free the full memory block
    allocated for the relevant TSub even though STL sees the type as
    T?

  3. Assume there is a defined method T::foo() and override TSub::foo().

    Will (*tIter)->foo() call T::foo() or TSub::foo() ?

The context is: each TSub is desired to be instantiated in singleton fashion, yet be stored in a manner allowing iterative consideration as the supertype, with methods overridden in the subclass being called.

I’d be very grateful for an informed explanation. Thank you for your time!

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:56:17+00:00Added an answer on May 25, 2026 at 6:56 am

    Will tsMap[*tIter] and tsMap.find(*tIter) both successfully find the
    correct associated value?

    Yes, but tsMap[*tIter] will create a default value if it doesn’t find the key.

    Will delete *tIter successfully free the full memory block allocated
    for the relevant TSub even though STL sees the type as T?

    If and only if the destructor of T is virtual

    Assume there is a defined method T::foo() and override TSub::foo().

    Will (*tIter)->foo() call T::foo() or TSub::foo() ?

    It will call T::foo if T::foo is not virtual. Otherwise it will call TSub::foo()

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