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Asked: May 11, 20262026-05-11T14:43:52+00:00 2026-05-11T14:43:52+00:00

Let’s suppose I have a bash script ( foo.sh ) that in a very

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Let’s suppose I have a bash script (foo.sh) that in a very simplified form, looks like the following:

echo 'hello' sleep 100 & ps ax | grep sleep | grep -v grep | awk '{ print $1 } ' | xargs kill -9 echo 'bye' 

The third line imitates pkill, which I don’t have by default on Mac OS X, but you can think of it as the same as pkill. However, when I run this script, I get the following output:

hello foo: line 4: 54851 Killed                  sleep 100 bye 

How do I suppress the line in the middle so that all I see is hello and bye?

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  1. 2026-05-11T14:43:53+00:00Added an answer on May 11, 2026 at 2:43 pm

    How about disown? This mostly works for me on Bash on Linux.

    echo 'hello' sleep 100 & disown ps ax | grep sleep | grep -v grep | awk '{ print $1 } ' | xargs kill -9 echo 'bye' 

    Edit: Matched the poster’s code better.

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