Question

Let’s suppose I have following two variables:

arg1=5
count5="test"

Now, I want to able to do something like:

echo ${'count' . $arg1} #which should give me "test" but its returning bad-substitution error

i.e. can part of a variable can be set as variable in bash?

Answer 1

Okay, got it working via indirect variable reference introduced in Bash v2 as:

my_var="count$arg1"
echo ${!my_var}