Question

li = [[{'foo': '1',
   'date': datetime.date(2011, 2, 1),
   'bar': 'a'},
  {'foo': '2',
   'date': datetime.date(2011, 2, 1),
   'bar': 'b'}],
 [{'foo': '2',
   'date': datetime.date(2011, 1, 30),
   'bar': 'f'},
  {'foo': '5',
   'date': datetime.date(2011, 1, 30),
   'bar': 'g'}]]

I want to convert this list into

     [{'date':datetime.date(2011, 2, 1), 
       'values':[{'foo': '1', 'bar': 'a'},{'foo':'2','bar': 'b'}]}, 
      {'date':datetime.date(2011, 1, 30), 
       'values':[{'foo': '2', 'bar':'f'},{'foo': '5','bar': 'g'}]}
     ]

Answer 1

Something like this?

dd = []
for l in li:
    d = {'date':l[0]['date'], 'values':[]}
    for ll in l:
        d['values'].append({'foo':ll['foo'], 'bar':ll['bar']})
    dd.append(d)



print dd

[{'date': datetime.date(2011, 2, 1),
  'values': [{'bar': 'a', 'foo': '1'}, {'bar': 'b', 'foo': '2'}]},
 {'date': datetime.date(2011, 1, 30),
  'values': [{'bar': 'f', 'foo': '2'}, {'bar': 'g', 'foo': '5'}]}]