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Home/ Questions/Q 666357
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:48:35+00:00 2026-05-13T23:48:35+00:00

Linux bash script: #!/bin/bash function Print() { echo $1 } var=* Print $var Execution

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Linux bash script:

#!/bin/bash

function Print()
{
    echo $1
}

var="*"
Print $var

Execution results:

alex@alex-linux:~/tmp$ ./sample-script 
sample-script

* is expanded to the list of files, which is actually script itself. How can I prevent this and see actual variable value? In general case, var can be more complicated than *, for example: home/alex/mydir/*.

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:48:35+00:00Added an answer on May 13, 2026 at 11:48 pm

    you need to escape your variables, too:

    Print "$var"
    

    And in your function:

    echo "$1"
    
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