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Asked: 2026-06-16T01:25:15+00:00

list = [’02’, ’03’, ’04’, ’05’, ’06’, ‘Inactive’, ‘Inactive’, ‘Inactive’, ‘Inactive’, ‘Inactive’] list.remove(‘Inactive’) print

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list = ['02', '03', '04', '05', '06', 'Inactive', 'Inactive', 'Inactive', 'Inactive', 'Inactive']

list.remove('Inactive')

print list

But it just leaves the result unchanged. What did I miss out?

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1 Answer

  1. Editorial Team

    It removed the first occurrence of Inactive as the documentation of list remove method says. To remove all occurrence, use loop/method/lambda/LC. For example: 

    myList = ['02', '03', '04', '05', '06', 'Inactive', 'Inactive', 'Inactive', 'Inactive', 'Inactive']
removedList = [x for x in myList if x!='Inactive'] # original list unchanged    
# or
removedList = filter(lambda x: x!='Inactive', myList) #leaves original list intact

    btw, do not use list as a variable name

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