Question

list = [('ba',4), ('hh',5), ('gg', 25)]

How do I do:

list.index(‘hh’) …and returns 1?

Then, how do I sort it by the 25, 5, 4?

What if I have 2 lists:

list1 = [('ba',4), ('hh',5), ('gg', 25)]
list2 = [('ja',40), ('hgh',88), ('hh', 2)]

how do I do a for each?

for item in l1:
    if item[0] in l2[0 of the tuple]:  

Answer 1

For the finding

>>> L = [('ba',4), ('hh',5), ('gg', 25)]
>>> [ i for i,l in enumerate(L) if l[0] == 'hh' ][0]
1

You need to decide what to do if it is found multiple times or not at all – the above will throw IndexError if not found and return the first if it is found multiple times.

For the sorting

>>> L = [('ba',4), ('hh',5), ('gg', 25)]
>>> sorted(L, key=lambda x: x[1])
[('ba', 4), ('hh', 5), ('gg', 25)]