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Home/ Questions/Q 7516553
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T01:10:05+00:00 2026-05-30T01:10:05+00:00

List<String> listStr = new ArrayList<String>(); if(listStr.size == 0){ } versus if(listStr.isEmpty()){ } In my

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List<String> listStr = new ArrayList<String>();

if(listStr.size == 0){

}

versus

if(listStr.isEmpty()){

}

In my view one of the benefits of using listStr.isEmpty() is that it doesn’t check the size of the list and then compares it to zero, it just checks if the list is empty. Are there any other advantages as I often see if(listStr.size == 0) instead of if(listStr.isEmpty()) in codebases? Is there is a reason it’s checked this way that I am not aware of?

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  1. Editorial Team
    Editorial Team
    2026-05-30T01:10:07+00:00Added an answer on May 30, 2026 at 1:10 am

    The answers to this question could give you the answer. Basically, in implementations of some lists the method isEmpty() checks if the size is zero (and therefore from the point of view of performance they are practically equivalent). In other types of lists (for example the linked lists), however, counting items require more time than to check if it is empty or not.

    For this reason it is always convenient to use the method isEmpty() to check if a list is empty. The reasons for which such a method is provided in all types of lists are also related to the interface, since ArrayList, Vector and LinkedList implement the same List interface: this interface has the isEmpty() method; then, each specific type of list provides its implementation of isEmpty() method.

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