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Home/ Questions/Q 1007681
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:39:18+00:00 2026-05-16T08:39:18+00:00

List(This,is,Scala).foreach(a => print(a+ )) compiles fine, but List(This,is,Scala).foreach(print(_+ )) fails complaining of missing parameter

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List("This","is","Scala").foreach(a => print(a+" "))

compiles fine, but

List("This","is","Scala").foreach(print(_+" "))

fails complaining of missing parameter type. I couldn’t figure out why it fails.

EDIT: I meant print not println – not that it makes logical difference.

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:39:18+00:00Added an answer on May 16, 2026 at 8:39 am

    The problem is that this

    List("This","is","Scala").foreach(print(_+" "))
    

    is not equivalent to

    List("This","is","Scala").foreach(a => print(a+" "))
    

    but to

    List("This","is","Scala").foreach(print(a => a+" "))
    

    Now, let’s see the type signature of foreach:

    def foreach [B] (f: (A) ⇒ B) : Unit
    

    where A is the type parameter of the List itself. Since we have a List[String], the compiler knows one has to pass to foreach a Function[String, B].

    In a => print(a+" ") the type of a is already known then: String.

    In print(a => a+" ") there is a problem, as print is not a Function. However, the compiler hasn’t considered that yet — it’s still trying to compile a => a+" ". So let’s look at the type of Predef.print:

    def print (x: Any) : Unit
    

    So a => a+" " must be of type Any, which, of course, means it can be anything. It doesn’t help the compiler in asserting what the type of a is. Which doesn’t really matter, because you didn’t want to print a Function in first place.

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