Question

Long time reader, first time poster. Any help is greatly appreciated.

I have crafted an AJAX query using JavaScript. The script works correctly, and the interface does what I want, but Firefox is giving me an error message related to the PHP file being hit. It’s strange, because it seems to suggest there’s a syntax error in the PHP, but that doesn’t make any sense. This is the error:

Error: syntax error
Source File: http://www.mysite.com/includes/ajax.php?action=checkpsudo&value=fd
Line: 1, Column: 1
Source Code:
yes

And the Javascript is below. Can anybody help me out? Thanks.

var ajaxobject = createajaxobjectObject();

function createajaxobjectObject() {
    if (window.XMLHttpRequest) { // Mozilla, Safari,...
        ajaxobject = new XMLHttpRequest();
        if (ajaxobject.overrideMimeType) {
            // set type accordingly to anticipated content type
            ajaxobject.overrideMimeType('text/xml');
        }
    } else if (window.ActiveXObject) { // IE
        try {
            ajaxobject = new ActiveXObject("Msxml2.XMLHTTP");
        } catch (e) {
            try {
                ajaxobject = new ActiveXObject("Microsoft.XMLHTTP");
            } catch (e) {}
        }
    }

    if (!ajaxobject) {
        alrt('Cannot create XMLHTTP instance');
        return false;
    }
    return ajaxobject; 
}

function checkpsudo(value) {    

    if (value == "") {
        document.getElementById('feedback').innerHTML = "Please select a psudonym";
        document.getElementById('feedback').className = "fail";
        document.getElementById('done').disabled=true;  
    } else {
        ajaxobject.onreadystatechange = function() { check(); };              
        ajaxobject.open('GET', '/includes/ajax.php?action=checkpsudo&value='+value, true);
        ajaxobject.send(null);  
    }


}

function check() {
    if (ajaxobject.readyState == 4) {

        //IF WE GOT OUR CHAT XML BACK CORRECTLY
        if (ajaxobject.status == 200) {             

            var response = ajaxobject.responseText;

            var value = document.getElementById('psudoentry').value;

            if(response=='no') {
                document.getElementById('feedback').innerHTML = "'" + value + "' is already being used";
                document.getElementById('feedback').className = "fail";
                document.getElementById('done').disabled=true;
            } else {
                document.getElementById('feedback').innerHTML = "'" + value + "' is available";
                document.getElementById('feedback').className = "success";
                document.getElementById('done').disabled=false;
            }                                          

        } else {
            alert('There was a problem with the request.');
        }
    }
}

Answer 1

My first instinct is that this is not a problem with your JS but with the XML being output by the PHP script.