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Home/ Questions/Q 7544969
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T08:48:36+00:00 2026-05-30T08:48:36+00:00

Look at following code: template <typename T, int d> class Grid { //Following line

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Look at following code:

template <typename T, int d>
class Grid {
   //Following line is what I need to change
   template<int d2> friend class Iterator<T,d,d2>;
}

template <typename T, int d, int d2>
class Iterator{ 
    //some code that use private fields of Grid<T,d>
}

template <typename T, int d>
class Iterator<T,d,0>{
    //This specialized class also need to use private parts of Grid<T,d>
}

Both specialized and not specialized Iterator should have access to private parts.
Line:

template<int d2> friend class Iterator<T,d,d2>;

does not compile with error: partial specialization `Iterator’ declared friend

Does anybody know how to replace it?

EDIT:
Thanks to @Xeo comment i was able to make a workaround:

template<typename TT, int dd, int d2> friend class Iterator;

However this gives friend access to all Iterator templates not only to those one that have matching first and second template parameter.

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  1. Editorial Team
    Editorial Team
    2026-05-30T08:48:37+00:00Added an answer on May 30, 2026 at 8:48 am

    This is just a workaround but it is working:

    template<typename TT, int dd, int d2> friend class Iterator;
    
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