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Home/ Questions/Q 6207771
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:41:30+00:00 2026-05-24T05:41:30+00:00

Looking at this example for implementing a Spirit parser, something caught me out when

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Looking at this example for implementing a Spirit parser, something caught me out when I was trying to write something similar.

The attribute template parameter of the grammar (std::map<std::string, std::string>()) and the signature template parameter of the rules (e.g. qi::rule<Iterator, std::string()> key, value) contain parentheses.

namespace qi = boost::spirit::qi;

template <typename Iterator>
struct keys_and_values
  : qi::grammar<Iterator, std::map<std::string, std::string>()> // <- parentheses here
{
    keys_and_values()
      : keys_and_values::base_type(query)
    {
        query =  pair >> *((qi::lit(';') | '&') >> pair);
        pair  =  key >> -('=' >> value);
        key   =  qi::char_("a-zA-Z_") >> *qi::char_("a-zA-Z_0-9");
        value = +qi::char_("a-zA-Z_0-9");
    }
    qi::rule<Iterator, std::map<std::string, std::string>()> query; // <- parentheses here
    qi::rule<Iterator, std::pair<std::string, std::string>()> pair; // <- parentheses here
    qi::rule<Iterator, std::string()> key, value; // <- parentheses here
};

I have never seen this before, and I unintentionally omitted then when writing my own version. This lead to my parser not generating the correct output run time (the output map is empty).

What is the purpose of these parentheses? My guess is that this makes the attribute of this rule an object of that type.

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:41:32+00:00Added an answer on May 24, 2026 at 5:41 am
    std::map<std::string, std::string>()
    

    This is a function type.

    The () makes this mean “a function that returns a std::map<std::string, std::string> and has no parameters.”

    Without the (), the type is just “std::map<std::string, std::string>,” which is not correct.

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