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Home/ Questions/Q 6146177
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T18:54:38+00:00 2026-05-23T18:54:38+00:00

looking at this test code: def a = test def expando = new Expando()

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looking at this test code:

def a = "test"

def expando = new Expando()

expando.a = a

expando.foobar = {a}

expando.a = "test1"

assert expando.foobar() != a

why the last assertion fail? it considers “a” as the local variable and not as the expando.a properties.

Thanks for help

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  1. Editorial Team
    Editorial Team
    2026-05-23T18:54:39+00:00Added an answer on May 23, 2026 at 6:54 pm

    Perhaps I am mistaken, but when you invoke expando.foobar(), it returns the result of the closure that was assigned to foobar. In this case, it is a, so it returns the value of a: test.

    expando.foobar() does not call the property ‘a’ because closures do not look for their delegate unless a variable is not defined in scope (and in this case it is).

    Edit:
    If you were to do expando.foobar = {delegate.a}, that would return the results you are expecting.

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