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Home/ Questions/Q 447057
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T21:31:57+00:00 2026-05-12T21:31:57+00:00

M = [[1,2,3], [4,5,6], [7,8,9]] col2 = [row[1] + 1 for row in M

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M = [[1,2,3],
     [4,5,6],
     [7,8,9]]

col2 = [row[1] + 1 for row in M if row[1] % 2 == 0]
print (col2)

Output: [3, 9]

I’m expecting it to filter out the odd numbers, but it does the opposite.

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  1. Editorial Team
    Editorial Team
    2026-05-12T21:31:57+00:00Added an answer on May 12, 2026 at 9:31 pm

    The code is doing exactly what you would expect – if the second item is even, increase it by one and put it into the list.

    So for the first row, it sees that 2 % 2 == 0 is True, and sets col2[0] = 2 + 1 = 3. For the second row, 5 % 2 == 0 is False. For the third row, 8%2 == 0 is True, and col2[1] = 8 + 1 = 9.

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