main.py:
import subone
import subtwo
subone.py:
a = 'abc'
subtwo.py:
print subone.a
Running python main.py throws a NameError: name 'subone' is not defined. I expected it to print ‘abc’.
Refactoring it to use from import and classes doesn’t help:
main.py:
from subone import * # Only using from X import * for example purposes.
from subtwo import *
print 'from main.py:', a.out
subone.py:
class A:
out = 'def'
a = A()
subtwo.py:
# This throws NameError: name 'a' is not defined
print a.out
# This throws NameError: name 'A' is not defined
b = A()
print b.out
BUT it will print ‘from main.py: def’. (It works when using import too.)
Why does it work this way? It seems like once subone is imported, it should be available to subtwo.
Is it because it’s bad programming to have imported modules depend on each other without going through their ‘parent’ module? Is there another, standard way to do this?
Update:
I now understand that the first example will not work because the line print subone.a doesn’t recognize the name subone, it not being in subtwo‘s namespace (even though it’s in main.py‘s), and it is being called from within the module subtwo. This can be fixed by using import subone at the top of subtwo.py — it will not re-load the module but will add it to subtwo‘s namespace so subtwo can use it.
But what about this:
main.py:
from subone import Nugget
from subtwo import Wrap
wrap = Wrap()
print wrap.nugget.gold
subone.py:
class Nugget:
gold = 'def'
subtwo.py:
class Wrap:
nugget = Nugget()
I would think that since Wrap and Nugget are both loaded directly into main‘s namespace, that they would use main‘s namespace and be able to reference each other, but it throws a NameError: name 'Nugget' is not defined. IS IT because Wrap is evaluated/checked from within subtwo‘s namespace BEFORE being loaded into main‘s namespace?
If you modified your subtwo.py this way then it will work
When you do subone.a in subtwo.py, you are trying to access the namespace subone in subtwo.py and in the namespace “subone”, there should be a attribute “a”.
When you do – import subone in subtwo.py, then subone is added to the namespace and subone namespace has attribute a. so subone.a will work.
I would also suggest that you play with dir() to see how namespaces are being added.
In subtwo.py, you can do the following:
Similarly, try adding “print dir()” before and after your import statements and the idea should become clear to you.
So in your above first example of main.py, subone.py and subtwo.py, the namespace in main.py will contain ‘subone’ and ‘subtwo’ while subtwo.py will have an empty namespace and can not access subone.a.
[Edit: Some more explanations]
Consider following files:
main.py
subone.py
subtwo.py
And the output of running main.py: