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Home/ Questions/Q 7791857
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T22:01:22+00:00 2026-06-01T22:01:22+00:00

map<string, string> dada; dada[dummy] = papy; cout << dada[pootoo]; I’m puzzled because I don’t

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map<string, string> dada;
dada["dummy"] = "papy";
cout << dada["pootoo"];

I’m puzzled because I don’t know if it’s considered undefined behaviour or not, how to know when I request a key which does not exist, do I just use find instead ?

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  1. Editorial Team
    Editorial Team
    2026-06-01T22:01:24+00:00Added an answer on June 1, 2026 at 10:01 pm

    The map::operator[] searches the data structure for a value corresponding to the given key, and returns a reference to it.

    If it can’t find one it transparently creates a default constructed element for it. (If you do not want this behaviour you can use the map::at function instead.)

    You can get a full list of methods of std::map here:

    http://en.cppreference.com/w/cpp/container/map

    Here is the documentation of map::operator[] from the current C++ standard…

    23.4.4.3 Map Element Access

    T& operator[](const key_type& x);

    1. Effects: If there is no key equivalent to x in the map, inserts value_type(x, T()) into the map.

    2. Requires: key_type shall be CopyConstructible and mapped_type shall be DefaultConstructible.

    3. Returns: A reference to the mapped_type corresponding to x in *this.

    4. Complexity: logarithmic.

    T& operator[](key_type&& x);

    1. Effects: If there is no key equivalent to x in the map, inserts value_type(std::move(x), T()) into the map.

    2. Requires: mapped_type shall be DefaultConstructible.

    3. Returns: A reference to the mapped_type corresponding to x in *this.

    4. Complexity: logarithmic.

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