Question

Map<String, String[]> map = request.getParameterMap();
for (Entry<String, String[]> entry : map.entrySet())
{
    String name = entry.getKey();
    String[] values = entry.getValue();
    String valuesStr = Arrays.toString(values).trim();
    LOGGER.warn(valuesStr);

I’m trying to look at a request parameter value using the code above.

Why does Arrays.toString(values).trim(); bracket the parameter value so it looks like this:

[Georgio]

What’s the best way to get the String here without the brackets?

If I do this:

String valuesStr = values[0].trim();

it seems there is a risk of losing subsequent values in the array.

Answer 1

That is just the default formatting applied by the Arrays.toString(Object[]) method. If you want to skip the brackets you can build the string yourself, for example:

public static String toString(Object[] values)
{
    StringBuilder sb = new StringBuilder();
    for (int i = 0; i < values.length; i++)
    {
        if (i != 0)
            sb.append(", ");
        sb.append(values[i].toString());
    }
    return sb.toString();
}