Question

Markup,

<span style="padding-left: 76px">
 <span style="padding-left:5px">
  <select id="select1" name="requestdbtype" value="<?php echo $type ?>">
   <?php
    $options = array('DB2' => 'DB2',
            'MySQL' => 'MySQL',
            'Oracle' => 'Oracle',
            'PostgreSQL' => 'PostgreSQL',
            'SQLite' => 'SQLite',
            'SQL Server' => 'SQL Server',
            'Sybase' => 'Sybase');
            foreach($options as $value => $type){
                          echo "<option value='$value'>".$row['requestdbtype']."</option>";
            }
      ?>
  </select>
 </span>
</span>

I’m having trouble displaying the options. The current option displayed should be the value of $row['requestdbtype']. But my display only shows the current value as all the options, please help.

Answer 1

You need to use $row['requestdbtype'] for comparison, not in your HTML. Note also the syntax of the select tag:

<select id="select1" name="requestdbtype">
<?php
$options = array('DB2' => 'DB2',
    'MySQL' => 'MySQL',
    'Oracle' => 'Oracle',
    'PostgreSQL' => 'PostgreSQL',
    'SQLite' => 'SQLite',
    'SQL Server' => 'SQL Server',
    'Sybase' => 'Sybase');
foreach ( $options as $value => $type ) : ?>
  <option value="<?php echo $value; ?>"<?php if ( $value == $row['requestdbtype'] ) echo ' selected="selected"'; ?>><?php echo $type; ?></option>
<?php endforeach; ?>
</select>