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Home/ Questions/Q 7934307
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:36:32+00:00 2026-06-03T21:36:32+00:00

Matcher.find finds the next subsequence, starting at a given index, which is compliant with

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Matcher.find finds the next subsequence, starting at a given index, which is compliant with the regex.

How can I make it so that it fails if the next character sequence is not compliant?

Ex:

    String input = "123456text123";
    Matcher mat1 = Pattern.compile("\\d+").matcher(input);

    mat1.find();
    System.out.println(mat1.group()); //123456
    mat1.find(mat1.end());
    System.out.println(mat1.group()); //123

I want to know if there’s a way to make the second find fail, since the next sequence does not match the mat1 pattern.

I want to be able to ‘compose’ matchers, in such a way that they MUST always be found in sequence.

Is it possible at all?

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  1. Editorial Team
    Editorial Team
    2026-06-03T21:36:34+00:00Added an answer on June 3, 2026 at 9:36 pm

    You can check that the previous mat1.end() equals the next mat1.start().

    int lastEnd = -1;
    while (mat1.find()) {
    
        // Was there any junk between last two matches?
        if (mat1.start() != lastEnd+1) {
            System.out.println("Fail.");
            break;
        }
    
        System.out.println(mat1.group());
        lastEnd = mat1.end();
    
    }
    
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