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Asked: 2026-05-20T00:11:12+00:00

Matching G in ‘Reference: G. ‘ using regular expression I tried using this but

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Matching G in ‘Reference: G. ‘ using regular expression

I tried using this but error still occur

refresidue = re.compiler(r'(s/Reference: \ //n)')

Any other suggestions as I’m quite new in this. Any help is most appreciated.

‘Reference: G. ‘ reference can be either A,C,G or T

I’m sorry about the confusion – what i would like to have is that the output only prints out the characters (A,C,G,T) instead of Reference: .

This is my code

refresidue = re.compiler(r'(s/Reference: \ //n)’)

a_matchref = refresidue.search(row[2])

if a_matchref is not None:

   a_matchref = a_matchref.group(1)
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1 Answer

  1. Editorial Team

    You’re mixing regex syntax from JavaScript (or some other regex flavor) and Python; and the regex itself is also quite strange. Also, re.compile() compiles a regex, it doesn’t match it to anything.

    Assuming you want to match a single alphanumeric character after the text Reference:, try the following:

    refresidue = re.search(r"Reference:\s*(\w)", your_text_to_be_matched).group(1)
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