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Home/ Questions/Q 6936019
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Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T12:10:45+00:00 2026-05-27T12:10:45+00:00

May be I missed something, but I’ve already beat my head with this one.

  • 0

May be I missed something, but I’ve already beat my head with this one.

I have defined CollectionViewSource:

<CollectionViewSource x:Key="packagesViewSource" d:DesignSource="{d:DesignInstance my:Package, CreateList=True}" />

and ListBox:

<ListBox Name="lstbPackages"
    SelectionChanged="lstbPackages_SelectionChanged"
    ItemsSource="{Binding Source={StaticResource packagesViewSource}}"
    DisplayMemberPath="Name"
    SelectedValue="{Binding Path=PackageId, UpdateSourceTrigger=Explicit}"
    SelectedItem="{Binding Path=Package}"
    SelectedValuePath="IdPackage"
/> 

Also, I have code-behind packagesViewSource initialization:

private IQueryable<Packages> GetPackagesQuery()
{
    IQueryable<Package> query = dc.PackagesList;
    // Returns an ObjectQuery.
    return query;
}

private void UserControl_Loaded(object sender, RoutedEventArgs e)
{
   ...
   packagesViewSource =((System.Windows.Data.CollectionViewSource)(this.FindResource("packagesViewSource")));
   queryPackages = this.GetPackagesQuery();
   packagesViewSource.Source = queryPackages.ToList();
   ...
}

And the line

packagesViewSource.Source = queryPackages.ToList();

involves event

private void lstbPackages_SelectionChanged(object sender, SelectionChangedEventArgs e)
{
   ...
}

and as you could guess

lstbPackages.SelectedItem != null

there.

What I do wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:10:46+00:00Added an answer on May 27, 2026 at 12:10 pm

    when you assign a source to your ListBox, a DefaultView of your packagesViewSource CollectionViewSource is created. and it has first element selected. So when assigning the source, do it in 3 step:

    1. Get DefaultView for your resource, then
    2. MoveCurrentToPosition(-1) on this view, then
    3. assign the View with correct current position to ListBox.
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